The angles of elevation of an artificial earth satellite, as measured from two earth stations are on the same side of it are 30°&60°.if the distance between the earth stations are 4000km, find the height of the satellite
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Dear Student,
◆ Answer -
h = 3464 km
◆ Explanation -
Let h be height of satellite from earth.
Horizontal distance of satellite from 1st point is -
l1 = h/tanθ1
l1 = h/tan30°
Horizontal distance of satellite from 2nd point is -
l2 = h/tanθ2
l2 = h/tan60°
Distance between two points is given.
l1 - l2 = h/tan30° - h/tan60°
4000 = h (1/tan30° - 1/tan60°)
4000 = h (1/0.5773-1/1.732)
h = 4000 / 1.155
h = 3464 km
Hence, height of satellite is 3464 km.
Hope this helps you.
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