The angles of elevation of the top of a hill at the city centres of two towns on either side of the hill are observed to be 45 degree and 60 degree. If the distance uphill from the first city centre is 12 km, then find in km, the distance uphill from the other city centre.
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philomath27:
You are correct my dear
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The distance uphill from the other city Centre is (12/√3).
Given:
the angle of elevations from the two towns are= 45 degree and 60 degree
distance of uphill from the first city Centre = 12 km
solution:
draw the diagram as per the question
AB= top hill
∠ABD= 45c
∠ACD=60°
BD= 12 km
let the distance of the uphill to other city is x.
solving
in
triangle ABD
tan 45° = AD/BD
⇒ 1= AD/12
⇒ AD= 12
Taking the triangle
ADC
tan 60°= AB/DC
⇒12/x = √3
⇒x= 12/√3
so distance from uphill from other city is 12/√3.
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