The angles of elevation of the top of a tower from two points at a distance of 4 m and 9 m from the base of the tower and in the same straight line with it are complementary. Prove that the height of the tower is 6 m.
Answers
Answered by
2
Answer:
Let AB be the hight of the tower = x m
BD be distance between foot of tower and 2nd point = 4m
BC be distance between foot of the tower and 1st point = 9m
CD be the distance between two points = 5m
To prove -> AB= 6m
Given /_ACB = θ , /_ADB = 90-θ
i.e., /_ ACB and /_ADB are complementary
Proof ---->
In above Picture
Attachments:
Similar questions