Math, asked by shaina14, 10 months ago

The angles of elevation of the top of a tower from two points P and Q at a distance of a and b respectively from the Base and in the same straight line with it are complementary. Prove that height of tower is underroot ab

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Answered by zaidfahimshaikh

Answer:

Step-by-step explanation:

AB is a tower. D and Care two points on the same side of a tower, BD = a and BC = b.

∠ADB and ∠ACB are the complementary angles.

If ∠ADB = x, then ∠ACB = 90 – x

In ∆ADB,

………… (1)

In ∆ABC,

…………....(2)

Multiplying (1) and (2),

(AB)2 = ab

AB = √ab

Height of tower = AB = √ab

Hence proved.

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Answered by singhdipanshu2707200

Answer:

Check your answer please

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