Math, asked by sheetal506, 1 year ago

the angles of heptagon are (x+3)°, (2x+5)°, ( x+8)°, (3x+1)°, (5x-6)°, (2x+9)°, and (x-5)°. calculate X.

Answers

Answered by priyanshu1812
0
sum of the interior angles of any polygon with n sides =
 = (n - 2) \times 180
so, a heptagon has 7 sides so sum of interior angles becomes 900°.

so,
x+3+2x+5+x+8+3x+1+5x-6+2x+9+x-5=900
=> 15x+15=900
=>15x=875
=>x=59

sheetal506: answer is 59
priyanshu1812: sorry wo chotti si galti ho gyi thi
priyanshu1812: plz mark it brainliest
Answered by bonisha33
3
(x+3)+(2x+5)+(x+8)+(3x+1)+(5x-6)+(2x+9)+(x-5)=900
= 15x+15=900
= x=900-15÷15
= x=885÷15
= x=59
hope this helps u
Similar questions