Question

the angles of quadrilateral are in A.P . whose common difference is 10° . find least angle in degree.​

Answer 1

Answer:

let the angles of the quadrilateral be X , X+10 . X+20 ,X+30

the sum of the angles of the quadrilateral = 360 degrees

X+ X+ 10 + X+20 +X +30 = 360

====> 4X +60 = 360

==>4X = 360 - 60 = 300

====> X = 75

The angles of the quadrilateral are 75, 85, 95, 105 degrees

Answer 2

Answer:

$The angles of Quadrilateral are :-\\ x , x + 10 , x + 20 , x + 30\\ as , d = 10\\\\s_{360} = x + x + 10 + x + 20 + x + 30 = 360\\s_{360} = 4x + 60 = 360\\ = 4x = 300\\ x = \frac{300}{4} \\ x = 75 \\therefore , \\ the requare angle is 75 \\which is also a smalllest angle . \\\\thank you .$

   thank you