Question

the angles of the quadrilater are in the ratio 1:2:3:4find the mesurement of angles
step by step explanation needed​

Answer 1

Step-by-step explanation:

let angles be 1x, 2x, 3x, 4x--------- 1.

let angles be 1x, 2x, 3x, 4x--------- 1.sum of all angles of quadrilateral = 360°

let angles be 1x, 2x, 3x, 4x--------- 1.sum of all angles of quadrilateral = 360° 1x+2x+3x+4x = 360°

let angles be 1x, 2x, 3x, 4x--------- 1.sum of all angles of quadrilateral = 360° 1x+2x+3x+4x = 360° 10x = 360°

let angles be 1x, 2x, 3x, 4x--------- 1.sum of all angles of quadrilateral = 360° 1x+2x+3x+4x = 360° 10x = 360° x = 360°÷10

let angles be 1x, 2x, 3x, 4x--------- 1.sum of all angles of quadrilateral = 360° 1x+2x+3x+4x = 360° 10x = 360° x = 360°÷10x = 36°

let angles be 1x, 2x, 3x, 4x--------- 1.sum of all angles of quadrilateral = 360° 1x+2x+3x+4x = 360° 10x = 360° x = 360°÷10x = 36°substitute the value of x in 1.

let angles be 1x, 2x, 3x, 4x--------- 1.sum of all angles of quadrilateral = 360° 1x+2x+3x+4x = 360° 10x = 360° x = 360°÷10x = 36°substitute the value of x in 1.1x = 1×36°=36°

let angles be 1x, 2x, 3x, 4x--------- 1.sum of all angles of quadrilateral = 360° 1x+2x+3x+4x = 360° 10x = 360° x = 360°÷10x = 36°substitute the value of x in 1.1x = 1×36°=36°2x = 2×36°=72°

let angles be 1x, 2x, 3x, 4x--------- 1.sum of all angles of quadrilateral = 360° 1x+2x+3x+4x = 360° 10x = 360° x = 360°÷10x = 36°substitute the value of x in 1.1x = 1×36°=36°2x = 2×36°=72°3x = 3×36°=108°

let angles be 1x, 2x, 3x, 4x--------- 1.sum of all angles of quadrilateral = 360° 1x+2x+3x+4x = 360° 10x = 360° x = 360°÷10x = 36°substitute the value of x in 1.1x = 1×36°=36°2x = 2×36°=72°3x = 3×36°=108°4x = 4×36°=144°

let angles be 1x, 2x, 3x, 4x--------- 1.sum of all angles of quadrilateral = 360° 1x+2x+3x+4x = 360° 10x = 360° x = 360°÷10x = 36°substitute the value of x in 1.1x = 1×36°=36°2x = 2×36°=72°3x = 3×36°=108°4x = 4×36°=144°angles of Quadrilateral are : 36°, 72°, 108°, 144°

let angles be 1x, 2x, 3x, 4x--------- 1.sum of all angles of quadrilateral = 360° 1x+2x+3x+4x = 360° 10x = 360° x = 360°÷10x = 36°substitute the value of x in 1.1x = 1×36°=36°2x = 2×36°=72°3x = 3×36°=108°4x = 4×36°=144°angles of Quadrilateral are : 36°, 72°, 108°, 144°HOPE IT HELPS!!!

Answer 2

Answer :

• The measures of angles of quadrilateral are 36⁰,72⁰,108⁰,144⁰

Given :

• The angles of the Quadrilateral are in the ratio 1 : 2 : 3 : 4

To find :

• Measures of angles

Solution :

• Let the angles of the Quadrilateral be x , 2x , 3x and 4x

As we know that,

• Sum of the angles of quadrilateral is 360⁰

》x + 2x + 3x + 4x = 360

》10x = 360

》x = 360/10

》x = 36⁰

Now we have to find the measures of angles ,

• x = 36⁰
• 2x = 2(36) = 72⁰
• 3x = 3(36) = 108⁰
• 4x = 4(36) = 144⁰

Hence , The measures of angles of quadrilateral are 36⁰,72⁰,108⁰,144⁰

More Explanation :

• Quadrilateral is a plane figure
• Quadrilateral has four sides or four edges
• Trapezium, squares , rectangle , parallelogram, rhombus are types of Quadrilateral
• Quadrilateral has four vertices and angles
• Sum of all angles of quadrilateral is 360⁰