the angles of the quadrilateral are in AP whose common difference is 10 degree find the angles
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Answer:
d=10
let angles be a,a+10,a+20,a+30
the sum of the four sides of quadrilateral is equal to 360
now,a+a+a+a+10+20+30=360
so. 4a+60=360
4a=300
so a=75
so the angles are : 75,85,95,105
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