Question

The angles of triangle are (98-x)°(2x+20)° (2x/5+45)° . find the angles of triangle

Answer 1

Step-by-step explanation:

The angles of triangle are (98-x)°,(2x+20)°, (2x/5+45)°

By condition,

(98-x)°+(2x+20)°+(2x/5+45)°=180°

(98-x)+(2x+20)+(2x/5+45)=180

98-x+2x+20+2x/5+45=180

-x+2x+2x/5+98+20+45=180

7x/5+163=180

7x/5=180-163

7x/5=17

x=17×5/7

x=85/7

1st angle=(98-85/7)°

=(601/7)°

2nd angle=(2x+20)°

=(2×85/7+20)°

=(170/7+20)°

=310/7°

3rd angle=(2x/5+45)°

=(2×85/7+45)°

=(170/7+45)°

=(485/7)°