Question

the angles of triangle are(x + 10 degree 0) ,(2x - 30 degree 0) and x degree 0 . find the value of x

Answer 1

We know that sum of all angles of a triangle is equal to 180°

So, (x+10)° + (2x-30)° + (x) ° = 180°

=> (x+2x+x)° + (10-30)° = 180°

=> (4x)° - 20° = 180°

=> 4x = 200

=> x=50 Ans

Answer 2

Angles of triangle=(x + 10°) ,(2x - 30° ) and x°

As we know sum of all angles of triangle is 180°

So we get-

(x + 10°)+(2x - 30° )+x°=180°

4x-20=180

4x=200

X=50°

The angles are-

1] x+10=50+10=60°

2] 2x-30=100-30=70°

3] x=50°