Question

The angles of triangle are (x+37),(2x+15), (3x+8). Find each angles of triangle.

Answer 1

let angle A= x+37, angle B= 2x+15 and angle C= 3x+8

we know that , A+B+C = 180°

∴(x+37)+(2x+15)+(3x+8)=180°

6x+ 60° = 180°

6x = 180°-60°

x = 120°/6

∴x=20°

∴angle A=20°+37 = 57°

angle B=2×20°+15 =40° +15° =55°

angle C =3×20°+8= 60°+8=68°