Math, asked by tripti3216, 1 year ago

THE ANGLES OF TRIANGLE ARE (X-5)DEGREE ,(2 X+10)DEGREE AND (3 X-5)DEGREE


ritzpro: so, what to find/
hazelreeva: complete your question
sumanath: the incomplete question might be to find all the angles of a triangle

Answers

Answered by sumanath
0
1st angle=x-5 ; 2nd angle=2x+10  ; 3rd angle=3x-5
The sum of angles of a triangle=180degree
=>x-5+2x+10+3x-5=180 (ANGLE SUM PROPERTY)
=>6x+0=180degree
=>x=180/6
=>x=30
1st angle=x-5
             =30-5
             =25degree.....................1
2nd angle=2x+10
              =2*30+10
              =60+10 
              =70degree.....................2
3rd angle=3x-5
             =3*30-5
             =90-5
             =85degree.........................3

                  We can check by..
     1st angle+2nd angle+3rd angle=180degree
     25degree+70degree+85degree=180degree
                                  180degree=180degree
                   










Answered by kvnmurty
0
The sum of measures of angles in a triangle is equal to 180 deg.

X - 5 + 2 X + 10 + 3 X - 5 = 180 deg \\ \\  X + 2 X + 3 X - 5 + 10  - 5 = 180 DEG \\ \\ 6 X + 0 = 180 deg \\ \\ X = 30 deg \\ \\ The\ measures\ of\ the\ angles\ are\ X-5 = 25\ deg,\ \ 2X+10 = 70\ deg\ \ \ 3X-5 = 85\ deg \\
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