THE ANGLES OF TRIANGLE ARE (X-5)DEGREE ,(2 X+10)DEGREE AND (3 X-5)DEGREE
ritzpro:
so, what to find/
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1st angle=x-5 ; 2nd angle=2x+10 ; 3rd angle=3x-5
The sum of angles of a triangle=180degree
=>x-5+2x+10+3x-5=180 (ANGLE SUM PROPERTY)
=>6x+0=180degree
=>x=180/6
=>x=30
1st angle=x-5
=30-5
=25degree.....................1
2nd angle=2x+10
=2*30+10
=60+10
=70degree.....................2
3rd angle=3x-5
=3*30-5
=90-5
=85degree.........................3
We can check by..
1st angle+2nd angle+3rd angle=180degree
25degree+70degree+85degree=180degree
180degree=180degree
The sum of angles of a triangle=180degree
=>x-5+2x+10+3x-5=180 (ANGLE SUM PROPERTY)
=>6x+0=180degree
=>x=180/6
=>x=30
1st angle=x-5
=30-5
=25degree.....................1
2nd angle=2x+10
=2*30+10
=60+10
=70degree.....................2
3rd angle=3x-5
=3*30-5
=90-5
=85degree.........................3
We can check by..
1st angle+2nd angle+3rd angle=180degree
25degree+70degree+85degree=180degree
180degree=180degree
Answered by
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The sum of measures of angles in a triangle is equal to 180 deg.
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