the angles of triangles are in ratio 3 : 7 : 8 find angles of triangle
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Answered by
1
Ratio given = 3:7:8
Let the angles be 3x;7xand 8x respectively
According to the ANGLE SUM PROPERTY sum of all angles of a triangle is 180degress
So
3x+7x+8x = 180
18x = 180
x = 10 degrees
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3x=30 degrees
7x= 70 degrees
8x= 80 degrees
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Hope you understood.
Let the angles be 3x;7xand 8x respectively
According to the ANGLE SUM PROPERTY sum of all angles of a triangle is 180degress
So
3x+7x+8x = 180
18x = 180
x = 10 degrees
.
.
.
.
.
.
3x=30 degrees
7x= 70 degrees
8x= 80 degrees
.
.
.
.
.
Hope you understood.
Dhrit2004:
Ratio given=3:7:8
yes I typed the same
Let the angles be=3x,7x,8x. According to the ASP(angle sum property) sum of the numbers=180 so, 3x+7x+8x=180. 18x=180. x=180/18 = 10
so angles of triangle=3x=3(10)=30, 7x=7(10)=70, 8x=8(10)=80
Therfore angles of the triangle are 30,70&80
thanks
wc
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Answered by
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Let the angles be x
3x+7x+8x= 180 (Angle sum property)
18x=180
x=180\18
x=18
3x=3x18=54
7x=7x18=124
8x=8x18=144
3x+7x+8x= 180 (Angle sum property)
18x=180
x=180\18
x=18
3x=3x18=54
7x=7x18=124
8x=8x18=144
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