Question

the angry Ariun carried some arrows for
ghting with Bheeshm. With half the
rows, he cut down the arrows thrown by
Bheeshm on him and with six other arrows
he killed the charioteer of Bheeshm. With
one arrow each he knocked down
respectively the rath, flag and bow of
Bheeshm. Finally, with one more than four
times the square root of arrows he laid
Bheeshm unconscious on an arrow-bed.
Find the total number of arrows Arjun had.​

Answer 1

Answer:

hey mate the answer is 100 arrows

x = x/2-9

x=4√x+1

x=4√x+1=x/2-9

so the answer is 100 by quadratic formula

Answer 2

Step-by-step explanation:

Let the number of arrows arjun had = 'x'.

(i)

Given that with half the arrows, he cut down the arrows thrown by Bheesm.

→ So, the number of arrows used to cut down the arrows of Bheesm = (x/2).

(ii)

Given that with six other arrows, he killed the rath driver of Bheesm.

→ So, the number of arrows used to kill the rath driver = 6.

(iii)

Given that one arrow each,he knocked down the rath,flag and bow of Bheesm.

→ So, the number of arrows used to knock rath,flag and bow = 3.

(iv)

Finally with one more than 4 times the square root of arrows he laid Bheesm unconscious.

→ 4√x + 1.

Now,

The total number of arrows carried by angry arjun :

→ x = (x/2) + 6 + 3 + 4√x + 1

→ 2x = x + 12 + 6 + 8√x + 2

→ 2x = x + 20 + 8√x

→ x = 20 + 8√x

→ x - 20 = 8√x

On squaring both sides, we get

→ (x - 20)^2 = (8√x)^2

→ x^2 + 400 - 40x = 64x

→ x^2 - 104x + 400 = 0

→ x^2 - 4x - 100x + 400 = 0

→ x(x - 4) - 100(x - 4) = 0

→ (x - 4)(x - 100) = 0

→ x = 100, 4{neglect - because he used more number of arrows}.

→ x = 100.

Therefore, the number of arrows Arjun had = 100.

Hope it helps!