Question

The angular displacement of a particle following circular path is given by θ( t )= 25t^3+ 3t +7, then angular velocity will be at t = 2 sec is​

Answer 1

Given:

The equation of the angular displacement as a function of time of a particle following a circular path = 25t³ + 3t +7

To find:

Angular velocity at time t =2 sec.

Solution:

As we know that upon differentiating the equation for angular displacement we would get the equation for angular velocity.

V = 25 t² + 3t + 7 / dt

V = 50t + 3

At time t =2 sec, the angular velocity will be:

V = 50*2 + 3

V = 103 m/s

Therefore, the angular velocity of the particle following a circular path will be 103 m/s.