the angular displacemnt of a particle moving along a circular path of radius r is 9pie/2 rad . the displacemnt of the particle is
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Answer:
√(2) r
Explanation:
9π/2 rad = 810° = 2 1/4 circle
since we are calculating displacement we will take only the 1/4 (90° )
for finding displacement
hypotenuse^2(displacement)= r^2 + r^2
=> displacement^2 = 2r^2
=> displacement = √(2r^2) =√(2) r
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