The angular momentum L vector=r vector×p vector,where r vector is a position vector and p vector is a linear momentum of a body.if r vector= 4i + 6j- 3k and p vector=2i + 4j - 5k.find L vector.
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We have given v= 4i unit= 6j unit-3k
by using this If the linear momentum of any particle is p=mv and its position vector from any constant point be r then abgular momentum of the particle is given by
L = r×p = m(r×v) (1)
Angular momentum is a vector quantity and its direction is perpandicular to the direction of r and p and could be found out by right hand screw rule.
From equation 1 scalar value or magnitude of angular momentum is given as
|L|=rpsinθ (2)
where V is the angle between r and p.
For a particle moving in a circular path
v=ω×r; (3)
where ω is the angular velocity
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Pls refer the attachment
hope it helps !
The values of r & p are different here in my attatchment but the method is same ....make sure to write the proper numbers.
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