Question

The angular momentum of a particle is varying as L=4t+8 when it moves in st line y=x-4.the force acting on particle would be?

Answer 1

Answer:

√2N

Explanation:

Torque acting on a particle is given by: τ=$\frac{dL}{dt}$

∴τ=$\frac{d(4t+8)}{dt}$=4 Nm

Also τ=(F)(r) where r is the perpendicular distance from the point (about which angular momentum is given or the point of axis)

Using this, 4=F(r)

r= Perpendicular distance of the given line from the origin

= $|\frac{(0)-(0)+4}{\sqrt{1^{2}+1^{2} } } |$ =2√2

∴F=$\frac{4}{2\sqrt{2} }$=√2N

Hope this answer helped you :)