The angular momentum of an electron in a given orbit is J, Its Kinetic Energy will be?
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According to Bohr
angular momentum of an electron = nh/2(pi)
hence,
mvr = nh/2(pi)
according to question angular momentum is “J”
means
nh/2(pi) = J
now
mvr = nh/2(pi)
squaring both sides
m2v2r2 = n2h2/4(pi)2
m2v2r2 = J2
now knietic energy = 1/2mv2
hence,
multiplying both sides my ½
1/2m2v2r2 = J2/2
1/2mv2 = J2/2r2m
Answered by
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△▼△▼ ђ๏ɭค❣ △▼△▼
According to Bohr,,
angular momentum of an electron = nh/2(pi)
hence,
mvr = nh/2(pi)
according to question angular momentum is “J”
means
nh/2(pi) = J
now
mvr = nh/2(pi)
squaring both sides
m2v2r2 = n2h2/4(pi)2
m2v2r2 = J2
now kinetic energy = 1/2mv2
hence,
multiplying both sides my ½
1/2m2v2r2 = J2/2
1/2mv2 = J2/2r2m
✧༺♥༻∞ ђ๏קє ย ɭเкє เՇ♥️ ˚*∞༺♥༻✧
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