Question

The angular momentum of electron in d orbital is equal to

Answer 1

The angular momentum of electron in d orbital is equal to √6 h/2π,by the formula √l (l+1) h/2π,where l=2 as it is d-orbital.

Answer 2

Answer : The angular momentum of electron in d orbital is equal to $\frac{h\sqrt{6}}{2\pi}$

Explanation :

As we know that the orbital angular momentum depends on the Azimuthal quantum number (l).

The formula of the orbital angular momentum is,

$L=\sqrt{l(l+1)}\frac{h}{2\pi}$

The value of 'l' for d-orbital = 2

Now put the value of 'l' in the above formula, we get the angular momentum.

$L=\sqrt{2(2+1)}\frac{h}{2\pi}$

$L=\frac{h\sqrt{6}}{2\pi}$

Therefore, the angular momentum of electron in d orbital is equal to $\frac{h\sqrt{6}}{2\pi}$