Question

The angular momentum of the electron in a hydrogen atom is 4.2178 × 10-34 kg.m2.s-1. Calculate the

energy of the orbit associated with the electron.​

Answer 1

Answer:

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Explanation:

Angular momentum (mvr)=nh2π=4.22×10−34kgm2s−1

∴n=4.22×10−34×2πh=2×4.22×10−34×3.146.626×10−34=4 (Given)

When the electron jumps from n = 4 to n = 3, the wavelength of the spectral line can be calculated as follows:

1λ=RH(1n21−1n22)=109,677cm−1(132−142)=109677×(19−116)=109677×7144cm−1

or λ=144109677×7cm=1.88×10−4cm

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