Question

the angular velocity of a rotating disc decreases linearly with angular displacement from 60 Revolution per minute to zero during 10 revolutions determine the angular velocity of the disc 3sec after it begins to slow down

Answer 1

$dN/dt=a$

$60/t=a 60= t x a$

$D=N(initial) * t + 0.5*a*t^{2} a*t=-60 10=60*t - 0.5*60*t 10=30*t t=1/3 minutes t=60/3=20 sec so at=60 a=-60/20=-3 so after 3 sec velocity = 60-3*3 =60-9= 51$