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In the above figure If LM parallel to CB and LN parallel to CD prove that AM =AN
AB. AD
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In∆ACB
LM//CB
So,by Thales theorem
AL/AC=AM/AB _1
Again
In ∆ACD
LN//CD
So, by Thales theorem
AL/AC=AN/AD _2
From equation 1 and 2
AL/AC=AM/AB
AL/AC=AN/AD
We know that if LHS is equal of two equations then RHS will also be equal.
Hence,
AM/AB=AN/AD
so,proved
LM//CB
So,by Thales theorem
AL/AC=AM/AB _1
Again
In ∆ACD
LN//CD
So, by Thales theorem
AL/AC=AN/AD _2
From equation 1 and 2
AL/AC=AM/AB
AL/AC=AN/AD
We know that if LHS is equal of two equations then RHS will also be equal.
Hence,
AM/AB=AN/AD
so,proved
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