The angular velocity of the particle is given by = 2t^3 − 6t
^2 + 3.
Find the time when its angular acceleration becomes zero.
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Answered by
1
Just differentiate the angular velocity and u will get angular acceleration....
So ang.acceleration a = 6t^2-12t
0= 6t^2 - 12t
t = 2 sec
Answered by
0
Answer:t=1s
Explanation:
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