Question

The annual increase in population of a town is 10%. Ir the increase in population from 2018 to 2017 is 7887, what was the population of the town in 2016​

Answer 1

Answer:

Population after 1 year =180000+180000× 10/100 = 198000  

Population after 2 years =198000+198000×  10/100  =217800

Answer 2

Answer:

the population in 2016 is 7170

Step-by-step explanation:

in 2017 population is 7887

the population in 2017 is 110% of the population in 2016.

Let the population in 2016 be x.

110% of x = 7887

110/100 × x =7887

x = 7887 /(110/100)

x = 7887 × 100/110

x = 7887 × 10/11

x = 717 × 10

x = 7170