Question

The annual rate of growth in population of a town is 10%.If its present population

is 26620,the population 3 years ago was?​

Answer 1

Answer:

Hey mate here is the answer

Step-by-step explanation:

Let the old population be X

A/Q

x+10% of X=26620

=x+10/100*X=26620

=x+X/10=26620

=10x+X/10=26620

=11x/10=26620

=x=26620*10/11

=x=24200

Hope it helps you ☺️☺️

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Answer 2

Three years ago the population was 20000.

Step-by-step explanation:

The present population is 26620 and the rate if growth is 10%.

The formula is:

$A=P(1+r)^t$

Here, A = final amount, P=initial amount, t = time, r= rate in decimal

We have to find the population 3 years ago.

Hence, we can find, P for

A = 26620

t = 3

r = 0.10

Substituting these values in above formula

$26620=P(1+0.10)^3\\\\P=\frac{26620}{1\left(1+0.10\right)^{3}}\\\\P=20000$

Hence, the population three years ago was 20000.

Learn More:

The present population of a town is 2024800. if the rate of growth of population is 5% per year find the increase population in 2 years.​

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