the answer is 2 option but how pls solve my question
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Step-by-step explanation:
Additive inverse: gives total sum equal to zero.
So, Additive inverse of [(4x)^3-3x +8] is [-(4x)^3+3x-8].
What should be added to [-(4x)^3+3x-8] to get -4.
= (-4)- [-(4x)^3+3x-8]
= (-4)+4x^3-3x+8
=4x^3-3x+4
Hence solved.
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