the answer is option 4 but explain how. ..clearly. . pls guys ..help me. .. fast ...
Answers
In Option 1 and 4, it can be seen clearly that the outermost electrons are closer to the nucleus, so they will require more ionization energy than rest. Now, in option 1 the 1st ionization energy (I.E) will be higher than option 4 because s subshell is fully filled in option 1 but not in option 4. But as 2nd I.E is asked so in option 4 after the removal of one electron ( 1st ionization) the next electron is in another subshell, unlike in the 1st option where we can still get the last electron from s subshell. Note here that the 3s subshell is farther than the 2p so removal of an electron from a 2p subshell will need more energy. Moreover the 2p subshell is fully filled so extra energy will be required. So 2nd I.E of option 4 will be the greatest. I hope you could follow.