Question

the apparent depth of a liquid in a party filled tank is 1.5 cm. more liquid is poured in a tank of height 1m. now the apparent depth appears to be 2.1m.find the refractive index of liquid using above data.

Answer 1

Answer:

Therefore, the refractive index of the liquid is 0.48

Explanation:

We know that if n is the refractive index of water then

$\boxed{n=\frac{\text{Real Depth}}{\text{Apparent Depth}}}$

If the real depth is R then

$n=\frac{R}{1.5}$

or, R = 1.5n

If the liquid is poured in the tank for height 1 m then the real depth becomes

R+100

Then

$n=\frac{R+100}{210}$

$\implies n=\frac{1.5n+100}{210}$

$\implies 210n=1.5n+100$

$\implies 208.5n=100$

$\implies n=\frac{100}{208.5}$

$\implies n=0.48$