Question

The apparent frequency of the whistle of an engine changes in the ratio 6:5 as the engine passes a stationary observer. If the velocity of sound is 330(m)/(s), then the velocity of the engine is

Answer 1

Answer:

$\frac{6}{5 } = \frac{vs - vo}{vs + vsr } \\ \frac{6}{5 } = \frac{330 - 0}{330 - v } \\ v = 55$

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Explanation:

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