The approximate energy levels of the hydrogen atom
are shown above. A certain hydrogen atom is in
the n = 2 state. In a single transition, this atom can
spontaneously emit a photon having an energy of 10.2eV
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Answer:
Transition of electron takes place from first excited state to ground state of Hydrogen atom.
∴ n
1
=1 and n
2
=2
Energy of photon released, E=13.6(
n
1
2
1
−
n
2
2
1
) eV
E=13.6(
1
2
1
−
2
2
1
)eV=13.6×
4
3
eV=10.2 eV
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