Chemistry, asked by sana41141, 7 months ago

The approximate energy levels of the hydrogen atom
are shown above. A certain hydrogen atom is in
the n = 2 state. In a single transition, this atom can
spontaneously emit a photon having an energy of 10.2eV

Answers

Answered by harshadabhole
1

Answer:

Transition of electron takes place from first excited state to ground state of Hydrogen atom.

∴ n

1

=1 and n

2

=2

Energy of photon released, E=13.6(

n

1

2

1

n

2

2

1

) eV

E=13.6(

1

2

1

2

2

1

)eV=13.6×

4

3

eV=10.2 eV

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