Question

The approximate radius of hydrogen atom is 0.05 NM and that of proton is 1.5 into 10 raise to the power minus 15 metre assuming both the hydrogen atoms and the proton to be spherical calculate fraction of the space in an atom of Hydrogen that is occupied by the nucleus

Answer 1

Area of a sphere :

A = 4πr²

Area of hydrogen atom :

Convert the nm to m

1nm = 1 × 10⁻⁹ M

3.142 × 4 × [0.05 × 10⁻⁹] ² = 3.142 × 10⁻²⁰ M²


Area of hydrogen proton:

3.142 × 4 × [1.5 × 10⁻¹⁵] ² = 2.8278 × 10⁻²⁹ M²

(2.8278 × 10⁻²⁹) ÷ (3.142 × 10⁻²⁰) = 9 × 10⁻¹⁰

Answer 2

Answer:

Explanation:

Area of a sphere :

A = 4πr²

Area of hydrogen atom :

Convert the nm to m

1nm = 1 × 10⁻⁹ M

3.142 × 4 × [0.05 × 10⁻⁹] ² = 3.142 × 10⁻²⁰ M²

Area of hydrogen proton:

3.142 × 4 × [1.5 × 10⁻¹⁵] ² = 2.8278 × 10⁻²⁹ M²

(2.8278 × 10⁻²⁹) ÷ (3.142 × 10⁻²⁰) = 9 × 10⁻¹⁰