Question

the are of a square field is 60025 square meter. a man cycles along its boundary at 18km per hour. in how much time will he return at the starting point?

Answer 1

Area of the field=$60025 m^{2}$
We know the formula
$Area= Side^{2}$ (for a square).
⇒60025=side²
⇒side=√60025
⇒side=+245 m or - 245 m.
Neglecting -ve value side=245 m.
⇒Perimeter=4*Side(For a square)
⇒P=245*4 m (Which is also the total distance)
⇒Speed= 18 km/h
⇒18 km/h=18*$\frac{5}{18}$ m/s=5 m/s.
⇒Time=$\frac{Distance}{Speed}$
⇒$\frac{245*4}{5} sec$
=49*4 seconds
 =196 seconds.
Ans:The required time is 196 seconds.
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Answer 2

Answer:

Area of the field=60025 m^{2}60025m2 

We know the formula

Area= Side^{2}Area=Side2 (for a square).

⇒60025=side²

⇒side=√60025

⇒side=+245 m or - 245 m.

Neglecting -ve value side=245 m.

⇒Perimeter=4*Side(For a square)

⇒P=245*4 m (Which is also the total distance)

⇒Speed= 18 km/h

⇒18 km/h=18*\frac{5}{18}185 m/s=5 m/s.

⇒Time=\frac{Distance}{Speed}SpeedDistance 

⇒\frac{245*4}{5} sec5245∗4sec 

=49*4 seconds

 =196 seconds.

Ans:The required time is 196 seconds.

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