The are of a square field is 60025 square meter. a man cycles along its boundary at 18km per hour. in how much time will he return at the starting point?
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Answered by
14
Ans :- 196 seconds
solution:-
area of square = 60025 square meter
side of square = √60025
(245 is square root of 60025)
side of square = 245 m
to cover up one side of sqaure time taken by man is
(245*60*60)/(18*1000) .....(1)
{ as the side of square in meters and the speed in in km/h so we will convert speed into m/s by dividing with 1000 and multiply with 60*60}
by solving (1) we get 49 sec
to covering 1 side the man take 49 sec
to reach at the starting point he has to cover 4 sides so 4×49 = 196 second s
solution:-
area of square = 60025 square meter
side of square = √60025
(245 is square root of 60025)
side of square = 245 m
to cover up one side of sqaure time taken by man is
(245*60*60)/(18*1000) .....(1)
{ as the side of square in meters and the speed in in km/h so we will convert speed into m/s by dividing with 1000 and multiply with 60*60}
by solving (1) we get 49 sec
to covering 1 side the man take 49 sec
to reach at the starting point he has to cover 4 sides so 4×49 = 196 second s
Answered by
8
L² = 60025m²
L=245m
Perimeter
=4L
=4x245
=980m
speed of the men
=18km per hour
=18000m per hour
time(hr)
=980/18000
=0.054 hour
=3.24 minutes
=196 seconds
L=245m
Perimeter
=4L
=4x245
=980m
speed of the men
=18km per hour
=18000m per hour
time(hr)
=980/18000
=0.054 hour
=3.24 minutes
=196 seconds
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