The are of equilateral triangle is numerically equal to its perimeter. Find its perimeter correct to 2decimal
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Answered by
2
And 4√3 = 6.92
Perimeter = 6.92 *3
Perimeter = 20.76
Perimeter = 6.92 *3
Perimeter = 20.76
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Answered by
6
Side of equilateral triangle = a units
Perimeter = 3a units
Area
![= \frac{ \sqrt{3} }{4} {a}^{2} = \frac{ \sqrt{3} }{4} {a}^{2}](https://tex.z-dn.net/?f=%3D++%5Cfrac%7B+%5Csqrt%7B3%7D++%7D%7B4%7D++%7Ba%7D%5E%7B2%7D)
Given that, Area = Perimeter
![\frac{ \sqrt{3} }{4} {a}^{2} = 3a \frac{ \sqrt{3} }{4} {a}^{2} = 3a](https://tex.z-dn.net/?f=+%5Cfrac%7B+%5Csqrt%7B3%7D+%7D%7B4%7D++%7Ba%7D%5E%7B2%7D++%3D+3a)
![\sqrt{3} {a}^{2} = 3a \times 4 \sqrt{3} {a}^{2} = 3a \times 4](https://tex.z-dn.net/?f=+%5Csqrt%7B3%7D++%7Ba%7D%5E%7B2%7D++%3D+3a+%5Ctimes+4)
![\sqrt{3} {a}^{2} = 12a \sqrt{3} {a}^{2} = 12a](https://tex.z-dn.net/?f=+%5Csqrt%7B3%7D++%7Ba%7D%5E%7B2%7D++%3D+12a)
![\sqrt{3} \times a \times a = 12 \times a \sqrt{3} \times a \times a = 12 \times a](https://tex.z-dn.net/?f=+%5Csqrt%7B3%7D++%5Ctimes+a+%5Ctimes+a+%3D+12+%5Ctimes+a)
![\sqrt{3} \times a = 12 \sqrt{3} \times a = 12](https://tex.z-dn.net/?f=+%5Csqrt%7B3%7D++%5Ctimes+a+%3D+12)
![a = \frac{12}{ \sqrt{3} } a = \frac{12}{ \sqrt{3} }](https://tex.z-dn.net/?f=a+%3D++%5Cfrac%7B12%7D%7B+%5Csqrt%7B3%7D+%7D+)
![a = \frac{4 \times 3}{ \sqrt{3} } a = \frac{4 \times 3}{ \sqrt{3} }](https://tex.z-dn.net/?f=a+%3D+++%5Cfrac%7B4+%5Ctimes+3%7D%7B+%5Csqrt%7B3%7D+%7D+)
![a = \frac{4 \times \sqrt{3} \times \sqrt{3} }{ \sqrt{3} } a = \frac{4 \times \sqrt{3} \times \sqrt{3} }{ \sqrt{3} }](https://tex.z-dn.net/?f=a+%3D++%5Cfrac%7B4+%5Ctimes++%5Csqrt%7B3%7D+%5Ctimes++%5Csqrt%7B3%7D++%7D%7B+%5Csqrt%7B3%7D+%7D+)
![a = 4 \sqrt{3} a = 4 \sqrt{3}](https://tex.z-dn.net/?f=a+%3D+4+%5Csqrt%7B3%7D+)
![a = 4 \times 1.73 a = 4 \times 1.73](https://tex.z-dn.net/?f=a+%3D+4+%5Ctimes+1.73)
![( \sqrt{3} = 1.73) ( \sqrt{3} = 1.73)](https://tex.z-dn.net/?f=%28+%5Csqrt%7B3%7D++%3D+1.73%29)
![a = 6.92 \: units a = 6.92 \: units](https://tex.z-dn.net/?f=a+%3D+6.92+%5C%3A+units)
Perimeter
![= 3a \\ = 3 \times 6.92 \\ = 20.76 \: units = 3a \\ = 3 \times 6.92 \\ = 20.76 \: units](https://tex.z-dn.net/?f=+%3D+3a+%5C%5C++%3D+3+%5Ctimes+6.92+%5C%5C++%3D+20.76+%5C%3A+units)
Perimeter = 3a units
Area
Given that, Area = Perimeter
Perimeter
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