Question

the area and sum of parallel sides of the trapezium 60 cm square and 12 cm find its hieght ​

Answer 1

Answer:

10cm

Step-by-step explanation:

given in image. hope it helps you

Answer 2

$\;\;\underline{\textbf{\textsf{ Given:-}}}$

• Area of the trapezium = 60 cm²

• Sum of parallel sides of the trapezium = 12 cm

$\;\;\underline{\textbf{\textsf{ Given:-}}}$

• Height of the trapezium, H

$\;\;\underline{\textbf{\textsf{ Solution :-}}}$

$\underline{\:\textsf{Let's try to know about trapezium :}}$

• A trapezium is a quadrilateral, which is defined as a shape with four sides and one set of parallel sides.

Formula for perimeter of a trapezium :-

• Perimeter = Sum of all the sides

$\underline{\:\textsf{ As we know that :}}$

$\tt{Area_{(trapezium)} = \dfrac{1}{2}\times Sum_{(parallel\:sides)} \times H}$

$\underline{\:\textsf{ Now, put the given values in the formula :}}$

$\tt{\longrightarrow 60 = \dfrac{1}{ \cancel{ \: 2 \: }} \times \cancel{12} \times H}$

$\tt{\longrightarrow 60 = 1 \times 6 \times H}$

$\tt{ \longrightarrow 60 = 6 \times H}$

$\tt{\longrightarrow 60 = 6H}$

$\tt{\longrightarrow \cancel{\dfrac{60}{6}} = H}$

$\bf{ \longrightarrow H= 10 \: cm}$

$\;\;\underline{\textbf{\textsf{ Hence-}}}$

$\underline{\textsf{ The height of the trapezium is \textbf{10 cm }}}.$

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