Question

The area at the end X of hydraulic jack is having a cross section area 0.005m and
Y it is 0.1m?. If a force of 10 N is applied at the end X, what is the force felt at Y?​

Answer 1

Answer:

o.5 newton

Explanation:

f2=a2/a1×f1

f1=.005/.1×10

f1=o.5 newton

Answer 2

Solution

In a hydraulic press a force

applied to the smaller plunger creats a pressure

in the liquid and this pessure is transmitted equally throughout the liquid and acts on the larger plunger. The thrust acting on te larger plunger upwards due to tis pressure is <br>

<br> Hence, the thrust on

is magnified by

times <br>

<br> b.

<br> work done by force