Question

The area of 4 walls of a room is 77msquare .the breadth and the length of the room is 7.5m and 3.5m respectively find the height of the room

Answer 1

$2(l \times h) + 2(b \times h) = 77 {m}^{2}$
where l,b & h are length,breadth & height respectively. that is
$2(3.5 \times h) + 2(7.5 \times h) = 77 \\ 7h + 15h = 77 \\ 22h = 77 \\ h = \frac{77}{22} = \frac{7}{2} = 3.5m$

Answer 2

$here \: is \: your \: answer$

$area \: of \: walls \: = 77 \: {m}^{2}$

length ( l ) = 7.5 m

breath (b ) = 3.5 m


↪2( l + b) h. = 77 

2 (7.5+3.5) h = 77

2 ×11 × h = 77

h = 77/22 

h= 7/2 

h= 3.5m .

$height \: of \: room \: is \: 3.5 \: m$

$hope \: it \: helps$

$\beta e \: \beta \gamma \alpha inly$