The area of 4walls of a cuboidal box is 256cm². If the length of box is 5times the height and breadth is 3times tha height, find the dimensions of the cuboidal box
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Here is your answer
Area of 4 walls = 256cm^2
Let the height be x
Length = 5x
Breadth = 3x
To find - Length , Breadth , Height
Calculation -
As we know the area of 4 walls is given .
Thus, it's lateral surface area of cuboid since it's area of 4 walls excluding the top and base.
Lateral surface area of cuboid - 2h ( l + b)
Thus,
2(x) [ 5x + 3x ] = 256
10x^2 + 6x^2 = 256
16x^2 = 256
Therefore x^2 = 256/16 = 16
=> x = √16 = 4
Thus we got the value of x = height = 4 cm
Length = 5x = 5(4) = 20 cm
Breadth = 3x = 3 (4) = 12 cm
Hope it helps :)
Here is your answer
Area of 4 walls = 256cm^2
Let the height be x
Length = 5x
Breadth = 3x
To find - Length , Breadth , Height
Calculation -
As we know the area of 4 walls is given .
Thus, it's lateral surface area of cuboid since it's area of 4 walls excluding the top and base.
Lateral surface area of cuboid - 2h ( l + b)
Thus,
2(x) [ 5x + 3x ] = 256
10x^2 + 6x^2 = 256
16x^2 = 256
Therefore x^2 = 256/16 = 16
=> x = √16 = 4
Thus we got the value of x = height = 4 cm
Length = 5x = 5(4) = 20 cm
Breadth = 3x = 3 (4) = 12 cm
Hope it helps :)
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