Math, asked by mysticd, 1 year ago

The area of a circular field is 616m^2 there is a path of uniform width 14m, out side the field .Find the area of the path.

Answers

Answered by lohithanaidu
2
Let the radius of the circular path be 'r' m.
Given, the area of the circular path is 616 m².
⇒πr²=616
⇒r²=616(7/22)
⇒r²=28×7
⇒r²=196
⇒r=√196
⇒r=14 m
Area of the path = π(R²-r²) where R=r+width(14m)
⇒(22/7)[(14+14)²-(14)²]
⇒(22/7)(784-196)
⇒(22/7)(588)
⇒22(84)
⇒1848 m²
Therefore, the area of the path is 1848 m².
Answered by Anonymous
0

Step-by-step explanation:

Let the radius of the circular path be 'r' m.

Given, the area of the circular path is 616 m².

⇒πr²=616

⇒r²=616(7/22)

⇒r²=28×7

⇒r²=196

⇒r=√196

⇒r=14 m

Area of the path = π(R²-r²) where R=r+width(14m)

⇒(22/7)[(14+14)²-(14)²]

⇒(22/7)(784-196)

⇒(22/7)(588)

⇒22(84)

⇒1848 m²

Therefore, the area of the path is 1848 m².

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