The area of a circular field is 616m^2 there is a path of uniform width 14m, out side the field .Find the area of the path.
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Let the radius of the circular path be 'r' m.
Given, the area of the circular path is 616 m².
⇒πr²=616
⇒r²=616(7/22)
⇒r²=28×7
⇒r²=196
⇒r=√196
⇒r=14 m
Area of the path = π(R²-r²) where R=r+width(14m)
⇒(22/7)[(14+14)²-(14)²]
⇒(22/7)(784-196)
⇒(22/7)(588)
⇒22(84)
⇒1848 m²
Therefore, the area of the path is 1848 m².
Given, the area of the circular path is 616 m².
⇒πr²=616
⇒r²=616(7/22)
⇒r²=28×7
⇒r²=196
⇒r=√196
⇒r=14 m
Area of the path = π(R²-r²) where R=r+width(14m)
⇒(22/7)[(14+14)²-(14)²]
⇒(22/7)(784-196)
⇒(22/7)(588)
⇒22(84)
⇒1848 m²
Therefore, the area of the path is 1848 m².
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Step-by-step explanation:
Let the radius of the circular path be 'r' m.
Given, the area of the circular path is 616 m².
⇒πr²=616
⇒r²=616(7/22)
⇒r²=28×7
⇒r²=196
⇒r=√196
⇒r=14 m
Area of the path = π(R²-r²) where R=r+width(14m)
⇒(22/7)[(14+14)²-(14)²]
⇒(22/7)(784-196)
⇒(22/7)(588)
⇒22(84)
⇒1848 m²
Therefore, the area of the path is 1848 m².
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