Question

the area of a convex quadrilateral ABCD if AC is perpendicular to BD AC = 3 cm and BD = 8 cm is

Answer 1

Answer:

(3*8) ÷2

=24÷2

=12 ans

By making diagram you will get that 3 cm and 8 cm are diagonal and it will be rhombus

So area of it is 1/2 *d1 * d2

Answer 2

Answer:

ΔAOB,ΔAOD

DO=OD ( mid point )

AO=OA (common side)

∠AOB=∠AOD (right angle )

So ΔAOB, ΔAOD

So AB=AD

And ∠ABc=∠ADC=90°

Similarly AB=BC=CD=AD can be proved that ABCD is a square