Math, asked by deonecollector, 9 months ago

The area of a living room is 80 m2. The length of the room is 2 m more than the width. What are the dimensions?

Answers

Answered by adithyasree482
7

Answer:

width =8m

length =10m

Step-by-step explanation:

area =80 m^2

length =2+width

area =(2 + width ) × width

let width =w

80= 2w + w^2

w^2 + 2w - 80 = 0

w^2 + 10w - 8w - 80 =0. (splitting middle term)

w(w +10) -8(w+10)= 0

(w+10) (w-8) =0

w=8m (taking positive)

Therefore width =8m

length = 80÷8 =10m

Answered by Vamprixussa
16

Let the width of the living room be x

=> Length of the living room = x + 2

Given

Area of the living room = 80 m²

=> x(x+2) = 80\\=> x^{2}  + 2x -80 = 0\\=> x^{2} + 10x-8x-80=0\\=> x(x+10)-8(x+10)=0\\=> (x-8)(x+10)=0

Now,

x+10 = 0\\=> x = -10

-ve value is not taken

∴ x = 8

\boxed{\boxed{\bold {Length\ of \  the  \ living \ room \ = 10 \ cm}}}

\boxed{\boxed{\bold{Breadth \ of \ the \ living \ room = 8 \ cm}}}

                                                       


Anonymous: Superb :)
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