Question

The area of a mans foot is 80cm sqaure. How much pressure will the man exert on the ground,while standing ,if his weight is 80kgf?

Answer 1

weight = 80 kgf = 80×9.8 N
two feet..so area becomes
area = 2*80 cm² = 160×10^-4 m²

pressure = (80*9.8)/(160×10^-4) = 9.8*10^4 Pa = 49 kPa

Answer 2

Area of  1 foot= 80X$10^{-4}$
Area of 2 feet=160X$10^{-4}$

Force=80kgf==80X9.8N

[tex]P= \frac{F}{A} [/tex]
P=$\frac{80X9.8}{ 160X10^{-4} }$
P=4.9X10⁴ Pa