The area of a parallelogram ABCD is 40 sq. cm.If X be the mid point of AD, find area of ∆AXB.
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20 cm square is the right answer.As it is on the same base AB and same ||AB and CD.
So area tri.ABX=1/2 area parallelogram ABCD.So 20 cm square is the answer.
Please mark me as brainliest.
So area tri.ABX=1/2 area parallelogram ABCD.So 20 cm square is the answer.
Please mark me as brainliest.
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