Question

the area of a parallelogram ABCD is 54 CM2 if one of the side is 12 cm find its height corresponding to the given base

Answer 1

Area of parallelogram = B × H
Area of parallelogram = 54 cm square
B × H =54 cm square
12 × H = 54 cm square
H. =
$54 \div 12$
H = 4.5 cm

Answer 2

Answer:

Required height is 4.5 cm.

Step-by-step explanation:

Given,area of a parallelogram ABCD is 54 square cm.

We know area of a parallelogram $= base \times height$

For example,

If base of a parallelogram is 20 m and height is 10 m then area of the parallelogram

$20 \times 10 \\ = 200 \: {m}^{2}$

Again if area of a parallelogram is 50 square m and base is 25 m then according to rule,

$area = base \times height \\ height = \frac{area}{base} \\ = \frac{50}{25} \\ = 2 \: m$

Here also given that area is 54 square cm and base is 12 cm.

So required height

$= \frac{area}{base} \\ = \frac{54}{12} \\ = \frac{9}{2} \\ = 4.5 \: cm$

Parallelogram related two more questions:

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