Question

the area of a parallelogram is 338 metre Square if its attitude is twice the corresponding base find the base and the altitude

Answer 1

area of parallelogram = base × height
let base be x
so the altitude is 2x
area =2x×x
338=2x^2
169=x^2
x=13
hence the base is 13m
and the altitude is 26m

Answer 2

GIVEN:

• Area of a parallelogram is 338 metre².
• Its attitude is twice the corresponding base.

TO FIND:

• What is the base and altitude of the Parallelogram ?

SOLUTION:

Let the base of the Parallelogram be 'b' m

and the height be 'h' m

If its attitude is twice the corresponding base.

$\rm{\implies h = 2b....1)}$

We know that the formula for finding the area of parallelogram is:-

$\bf{\star \: Area = Base \times Height \: \star}$

Put the value of h from equation 1)

$\rm{\implies 338 = b \times 2b}$

$\rm{\implies 338 = 2b^2}$

$\rm{\implies \cancel\dfrac{338}{2} = b^2}$

$\rm{\implies 169 = b^2}$

$\rm{\implies \sqrt{169} = b}$

$\bf{\implies 13 \: m = b }$

Put the value of 'b' in equation 1)

$\rm{\implies h = 2 \times 13}$

$\bf{\implies h = 26 \: m}$

❝ Hence, the height of the Parallelogram is 26 m and base of parallelogram is 13 m ❞

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