the area of a parallelogram is 392 m square if its altitude is twice the corresponding base determine the base and height
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Answered by
13
Let, base be x.
Thn, alt. = height = 2x
Ar(Parallelogram) = b x h
392 = (x) (2x)
196 = x²
x = 14
Base = x = 14
Height = 2x =28
Thn, alt. = height = 2x
Ar(Parallelogram) = b x h
392 = (x) (2x)
196 = x²
x = 14
Base = x = 14
Height = 2x =28
Answered by
6
Hey!!!!
____________
let the base of the parallelogram be x and altitude (height) be y.
Then ATQ,
=> y = 2x -------(1)
=> Area = 392 cm²
We know Area = altitude x base
=> xy = 392
Using (1) in above equation
=> x(2x) = 392
=> 2x² = 392
=> x² = 196
=> x = √196
=> x = 14
Thus y = 28
Thus the height of the parallelogram is 28cm and base is 14cm
___________
Hope this helps ✌️
Good Night :-)
____________
let the base of the parallelogram be x and altitude (height) be y.
Then ATQ,
=> y = 2x -------(1)
=> Area = 392 cm²
We know Area = altitude x base
=> xy = 392
Using (1) in above equation
=> x(2x) = 392
=> 2x² = 392
=> x² = 196
=> x = √196
=> x = 14
Thus y = 28
Thus the height of the parallelogram is 28cm and base is 14cm
___________
Hope this helps ✌️
Good Night :-)
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