The area of a parallelogram whose length is 30cm ,width is 20cm and 1 diagnol is 40cm ,is
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let ABCD is a given parallelogram
AB = c = 30cm
BC =a=20cm
AC =b = 40cm
ABC is an isosceles triangle
s= (a+b+c)/2 =(30+20+40)/2 = 90/2 =45
area of ABC = √s(s-a)(s-b)(s-c)
= √45(45-20)(45-40)(45-30)
=√45*25*5*15
=√9*5*5*5*5*5*3
=3*5*5*√15
=75√15
area of the parallelogram = 2* area of triangleABC
= 2*75√15
=150√15
AB = c = 30cm
BC =a=20cm
AC =b = 40cm
ABC is an isosceles triangle
s= (a+b+c)/2 =(30+20+40)/2 = 90/2 =45
area of ABC = √s(s-a)(s-b)(s-c)
= √45(45-20)(45-40)(45-30)
=√45*25*5*15
=√9*5*5*5*5*5*3
=3*5*5*√15
=75√15
area of the parallelogram = 2* area of triangleABC
= 2*75√15
=150√15
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