The area of a parallelogram whose sides are a = ( i + 2 j + 2 k) m and b = (2 i + 4 j + 5 k) m, is:
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If a and b be the adjacent sides of a parallelogram then the diagonals are
AC
=a+b,
BD
=b−a
∴ Unit vectors are
∣
∣
∣
∣
AC
∣
∣
∣
∣
AC
and
∣
∣
∣
∣
BD
∣
∣
∣
∣
BD
.
Area of parallelogram =∣a×b∣.
Ans.
7
1
(3i+6j−2k)×
(69)
1
(−i−2j+8k)=11
5
sq.units.
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