Question

The area of a pathway which is in the shape of a ring with outer circumference 416 m and inner circumference 376 m is​

Answer 1

Answer:

let the inner radius=r=376m

outter radius=R=416m

now ,

Area of the pathway (A)=π(R+r)(R-r)

=π(416+376)(416-376)

=π(792)(40)

=π ×31680

=(22/7)×31680

=99565.71 m^2

hope it helps you friend